3.16=n^2-54

Solution for 3.16=n^2-54 equation:

3.16=n^2-54

We move all terms to the left:

3.16-(n^2-54)=0

We get rid of parentheses

-n^2+54+3.16=0

We add all the numbers together, and all the variables

-1n^2+57.16=0

a = -1; b = 0; c = +57.16;
Δ = b2-4ac
Δ = 02-4·(-1)·57.16
Δ = 228.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{228.64}}{2*-1}=\frac{0-\sqrt{228.64}}{-2}
=-\frac{\sqrt{}}{-2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{228.64}}{2*-1}=\frac{0+\sqrt{228.64}}{-2}
=\frac{\sqrt{}}{-2}
$